A2-b2-a2-b2-b2-a2b2-a2 How-

Both side same it's just rearrangement of negative sign .if you put value instead of a amp;b there will be same result both sides. ...

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Factors Affecting Friction

a2+b2-a2+b2=b...

Question

(a²+b²)(-a²+b²)=(b²+a²)(b²-a²) How?

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The length of the chord intercepted by the circle $x^{2} + y^{2} = r^{2}$ on the line $\frac{x}{a} + \frac{y}{b} = 1$

∣ ∣ ∣ ∣ ∣ \begin{matrix} - a^{2} & a b & a c a b & - b^{2} & b c a c & b c & - c^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ + ∣ ∣ ∣ ∣ ∣ \begin{matrix} a^{2} & - b^{2} & - c^{2} - a^{2} & b^{2} & - c^{2} - a^{2} & - b^{2} & c^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ =

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}}

(a^{2} b^{2} c^{3} - a^{2} b^{2} c^{3} + a^{2} b^{2} c^{3}) \div a^{2} b^{2} c^{3}

\frac{a + \sqrt{a^{2} - b^{2}}}{a - \sqrt{a^{2} - b^{2}}} + \frac{a - \sqrt{a^{2} - b^{2}}}{a + \sqrt{a^{2} - b^{2}}}

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