A 2- b 2- c 2- ab - bc - ca equals-A- a-b-c2B- a-b-c2C- 1-2-a-b2-b-c2-c-a2-D-a-b-c2

The correct option is C a2 + b2 + c2 ab bc ca = 1/2(2a2 + 2b2 + 2c2 2ab 2bc 2ca) = 1/2(a2 2ab + b2 + b2 2bc + c2 + c2 2ca + a2) = 1/2[(a ...

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Factor of Polynomials

a 2+ b 2+ c 2...

Question

a² + b² + c² - ab - bc - ca equals:

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Find:
$(a + b + c) \times (a + b - c) =$

In a triangle ABC, $2 c a s i n \frac{A - B + C}{2}$ is equal to

a^{2} + b^{2} + c^{2} - a b - b c - c a = \frac{1}{2} [{(b - c)}^{2} + {(c - a)}^{2} + {(a - b)}^{2}]

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

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