a³ + b³ + a + b

Open in App

Solution

The given expression to be factorized is

This can be written as

=

Recall the formula for sum of two cubes

Using the above formula, we have

Take common. Then we have

We cannot further factorize the expression.

So, the required factorization of is.

Suggest Corrections

Similar questions

a^{3} (b - c)^{3} + b^{3} (c - a)^{3} + c^{3} (a - b)^{3}

a^{3} {(b - c)}^{3} + b^{3} {(c - a)}^{3} + c^{3} {(a - b)}^{3}

∣ ∣ ∣ ∣ \begin{matrix} a - b & b + c & a b - c & c + a & b c - a & a + b & c \end{matrix} ∣ ∣ ∣ ∣

a^{3}

b^{3}

(a - b)^{3}

{(a + b + c)}^{3} - a^{3} - b^{3} - c^{3} = 3 (a + b) (b + c) (c + a)

{(a + b + c)}^{3} - a^{3} - b^{3} - c^{3} = [{(a + b + c)}^{3} - a^{3}] - [b^{3} + c^{3}]

Join BYJU'S Learning Program