Question

A837B is divisible by 88. Find the digits A and B

Answer 1

Since A837B is divisible by 88 = 8×11 ,

then it's divisible by both 8 and 11.

Now, in order a number to be divisible by 8 its last three digits must be divisible by 8,

So 37B must be divisible by 8.

That's only possibly if B=6

--> 376/8=47.

So,

now our number is A8376

Next, in order a number to be divisible by 11 the difference between the sum of the odd numbered digits (1st, 3rd, 5th...) and the sum of the even numbered digits (2nd, 4th...) must be divisible by 11.

So, (A+3+6)-(8+7)= A-6 must be divisible by 11, which means that A can only be 6.

Hence the number is 68376.

A=6 and B= 6

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