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Mole Concept & Avogadro Number

AB2 and A2B...

Question

$A B_{2}$ and $A_{2} B_{3}$ are two compounds of the elements A and B. 0.15 mole of each of these compounds weighs 9.3 and 15.9 g respectively. Find the atomic masses of A and B.

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Solution

Let molar mass of A be $x g m o l e^{- 1}$
Let molar mass of B be $y g m o l e^{- 1}$

$N u m b e r o f m o l e s = \frac{G i v e n m a s s}{M o l a r m a s s}$

0.15= $\frac{9.3}{x + 2 y}$ and 0.15 = $\frac{15.9}{2 x + 3 y}$

$x + 2 y = 62$ and $2 x + 3 y = 106$

$y = 18 g m o l e^{- 1}$ and $x = 26 g m o l e^{- 1}$ .

Hence the atomic mass of x is $26 u$ and y is $18 u$

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