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Definition of Function

AB2g is disso...

Question

${A B}_{2} (g)$ is dissociates as ${A B}_{2} (g) ⇌ {A B}_{2} (g) + \frac{1}{2} B_{2} (g)$
When the initial pressure of ${A B}_{3}$ is $800$ torr and the total pressure developed at equilibrium is $900$ torr. What fraction of ${A B}_{2} (g)$ is dissociated?

10

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25

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Solution

The correct option is C $25$ %
$A B_{3 (g)} ⟶ A B_{2 (g)} + \frac{1}{2} B_{2 (g)} a o o a - a α a α \frac{a α}{2}$
Where $α$ is the degree of dissociation.
$a = 800 t o r r$
$a - a α + a α + \frac{a α}{2} = 900 α = \frac{1}{4}$
$%$ dissociated $= α \times 100 = \frac{1}{4} \times 100 = 25 %$

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