AB and CD are two chords of a circle with centre O such that AB - CD - E and F are the midpoints of AB and CD respectively- Then-Statement 1- OE - OFStatement 2- - AOB - CODA- Both statement 1 and statement 2 are true-B- Statement 1 is false- while statement 2 is true-C- Both statement 1 and statement 2 are false-D- Statement 1 is true- while statement 2 is false-

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AB and CD are...

Question

AB and CD are two chords of a circle with centre O such that AB > CD. E and F are the midpoints of AB and CD respectively. Then:
Statement 1: OE > OF
Statement 2: $∠ A O B > ∠ C O D$

Both statement 1 and statement 2 are true.

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Statement 1 is true, while statement 2 is false.

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Statement 1 is false, while statement 2 is true.

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Both statement 1 and statement 2 are false.

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Statement 1: In the figure areas of both parallelogram ABCD and the triangle ABE are equal.

Statement 2: Both the triangle and parallelogram have same base and height.

Pick the correct option

Statement1 : $c o s^{2} A$ + $s i n^{2} A$ = 1

Statement2 : $s e c^{2} A$ + $t a n^{2} A$ = 1

Statement 1: If B^{- 1} = ⎡ ⎢ ⎣ \begin{matrix} 0 & 6 & 7 8 & 9 & 10 11 & 12 & 13 \end{matrix} ⎤ ⎥ ⎦ and A = ⎡ ⎢ ⎣ \begin{matrix} 5 & 6 & 7 8 & 9 & 10 11 & 12 & 13 \end{matrix} ⎤ ⎥ ⎦, then (A B)^{- 1} does not exist Statement 2 : Since | A | = 0, (A B)^{- 1} = B^{- 1} A^{- 1} is meaningless.

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