AB and CD are two common tangents to circles which touch each other at C. If D lies on AB such that CD = 4 cm, then AB is equal to

4 cm

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6 cm

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8 cm

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12 cm

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Solution

The correct option is A 8 cm
From the given figure, CD = 4 cm
$C D = A D = 4$ (tangents drawn from an exterior point are equal)
$C D = B D = 4$ (tangents drawn from an exterior point are equal)
Now, $A B = A D + B D = 4 + 4 = 8$ cm

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Similar questions

A B ∥ C D

A B ∥ C D

In the given figure, BOC is a diameter of a circle with centre O. If AB and CD are two chords such that AB||CD and AB = 10 cm then CD = ?

(a) 5 cm

(b) 12.5 cm

(d) 10 cm

A B

C D

P

C P = 4 c m, A P = 8 c m, P B = 2 c m

P D

A P = 12 c m, A B = 15 c m, C P = P D

C D

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