Question

AB and CD are two equal chords of a circle with centre O such that $\angle AOB={80}^{\circ }$. Then, $\angle COD$ = ?

(a) ${100}^{\circ }$

(b) ${80}^{\circ }$

(c) ${120}^{\circ }$

(d) ${40}^{\circ }$

Answer 1

ANSWER:
(b) 80 °
Given: AB = CD
We know that equal chords of a circle subtend equal angles at the centre.
∴ ∠COD = ∠AOB = 80°