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Perpendicular from the Center to a Chord Bisects the Chord

A B and C D a...

Question

AB and CD are two equal chords of a circle with centre O such that ∠AOB = 80°, then ∠COD = ?
(a) 100°
(b) 80°
(c) 120°
(d) 40°

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Solution

(b) 80°
Given: AB = CD
We know that equal chords of a circle subtend equal angles at the centre.
∴ ∠COD = ∠AOB = 80°

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