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Question

AB and CD are two parallel chords of a circle of radius 3 cm. If AB=4 cms and CD=5 cm. Then the distance between them (in cm) is

A
52+11
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B
5+11
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C
5+112
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D
2+115
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Solution

The correct option is C 5+112
Let AB and CD be two parallel chords.
Radius =3cm

Now from OFB,
OF2=94=5,OF=5

From OEC,
OE2=9254=114OE=112

So distance between AB and CD
=OF+OE=5+112

377394_205227_ans.PNG

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