AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠BEF. If ∠LEB=35∘ then ∠CFQ will be:
AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB=350, then ∠CFQ will be
In the given figure, AB || CD and a transversal t cuts them at E and F respectively. If EG and FG are the bisectors of ∠BEF and ∠EFD respectivley, prove that ∠EGF=90∘