AB and CD are two slabs. The medium between the slabs has refractive index 2. Find the minimum angle of incidence at Q so that the ray is totally reflected by both the slabs

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Solution

The correct option is A 60 $^{\circ}$
$θ_{c r i c} m_{1} m_{2} = s i n^{- 1} (\frac{\sqrt{3}}{2}) = 60^{0}$

$θ_{c r i c} m_{2} m_{3} = s i n^{- 1} (\frac{1}{\sqrt{2}}) = 45^{0}$

$θ \geq 60^{0}$

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AB and CD are two slabs. The medium between the slabs has refractive index 2. Find the minimum angle of incidence at Q so that the ray is totally reflected by both the slabs

The correct option is A 60∘θcricm1m2=sin−1(√32)=600θcricm2m3=sin−1(1√2)=450θ≥600

The correct option is A 60 $^{\circ}$
$θ_{c r i c} m_{1} m_{2} = s i n^{- 1} (\frac{\sqrt{3}}{2}) = 60^{0}$

$θ_{c r i c} m_{2} m_{3} = s i n^{- 1} (\frac{1}{\sqrt{2}}) = 45^{0}$

$θ \geq 60^{0}$