Question

AB and CD interest at O. $\angle ACD=\angle BDC$, then

• A. $\angle AOC>\angle BOD$
• B. $AC=BD$
• C. AB and CD bisects each other
• D. $OB=OD$

Answer 1

The correct option is D $OB=OD$

$\widehat{ACD}=\widehat{ABD}$ (angles on same arc)
$\widehat{ACD}=\widehat{BDC}$ (given) $\Rightarrow \widehat{ABD}=\widehat{BDC}$
$\Rightarrow OB=OD$