$A B$ band $C D$ bisect each other at $K$ . Prove that $A C = B D$

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Solution

As $A B$ and $C D$ bisect each other
$\Rightarrow A K = B K, C K = D K$
also $∠ A K C = ∠ B K D$
$\Rightarrow △ A K C ≅ △ B K D$ by SAS congrueney
$\Rightarrow A C = B D$ by C.P.C.T. (corresponding parts of congruent triangles)

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