AB, BC and CD are the three consecutive sides of a regular polygon. If ∠BAC=15∘. Find each interior angle of the polygon.
A
147∘
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B
162∘
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C
150∘
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D
140∘
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Solution
The correct option is D150∘ AB, BC and CD are three consecutive sides of a regular polygon and ∠BAC=15o, In △BAC,AB=BC, Therefore, ∠BCA=∠BAC=15o (Isosceles Triangle) Now, ∠BCA+∠BAC+∠ABC=180o 15o+15o+∠ABC=180o ∠ABC=150o Each interior angle = 150o