AB^ BC, BD^ AC and CE bisects ∠C,∠ A = 30∘. Then what is CED? (CAT 1995)
∠ACB= 60
∠DCE= ∠ECB= 30
Therefore, ∠CED= 60. Option (b)
In the figure, it is given that ∠A = 90∘, AB = AC, and point D bisects the side BC. Find ∠ADC.
In the given figure, ABCD is a parallelogram, M is the midpoint of BD and BD bisects ∠B as well as ∠D. Then, ∠AMB= ?
(a) 45∘
(b) 60∘
(c) 90∘
(d) 30∘