Question

AB, BC, CD, DE and EF are 5 vectors as shown in the figure.

Joining which 2 points will give the magnitude of resultant of $\overline{AB}+\overline{BC}+\overline{CD}+\overline{DE}+\overline{EF}$

• A. A & E
• B. A & F
• C. A & D
• D. A & C

Answer 1

The correct option is B A & F

To get the resultant vector of these 5 vectors we just have to join the initial point of first vector which is ‘A’ to the terminal point of last vector which is ‘F’. So joining A and F will give $\overline{AB}+\overline{BC}+\overline{CD}+\overline{DE}+\overline{EF}$
So $\overline{AF}=\overline{AB}+\overline{BC}+\overline{CD}+\overline{DE}+\overline{EF}$