Question

AB,CD and EF are three concurrent lines passing through point O such that OF bisects $\angle BOD$ if $\angle BOF={35}^{\circ }$, find $\angle BOC$.

Answer 1

Given that $AB,CD\&EF$ are three concurrent lines passing through point $O$.

Then, $\angle BOF=\angle FOD={35}^0$

Since, $CD$ is straight line.

Now, we know that,

$\angle BOF+\angle FOD+\angle BOC={180}^0$

$\Rightarrow {35}^0+{35}^0+\angle BOC={180}^0$

$\Rightarrow \angle BOC={180}^0-{70}^0$

$\Rightarrow \angle BOC={110}^0$