Question

$AB$ crystallises in a bcc lattice with edge length an equal to 387 pm. The distance between two oppositely charged ions in the lattice is:

• A. 335 pm
• B. 250 pm
• C. 200 pm
• D. 300 pm

Answer 1

The correct option is A 335 pm

The distance b/w them would be:

$2r=\sqrt{(}3)\times \frac{a}{2}$

$2r=387\times \frac{\sqrt{3}}{2}=335pm$ approx.

This would be the distance b/w the two opposite charges.