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AB crystallis...

Question

$A B$ crystallises in a bcc lattice with edge length an equal to 387 pm. The distance between two oppositely charged ions in the lattice is:

A

335 pm

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B

250 pm

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C

200 pm

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D

300 pm

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Solution

The correct option is A 335 pm

The distance b/w them would be:

$2 r = \sqrt{(} 3) \times \frac{a}{2}$

$2 r = 387 \times \frac{\sqrt{3}}{2} = 335 p m$ approx.

This would be the distance b/w the two opposite charges.

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