Question

AB is 17.32 cm
If true then enter $1$ and if false then enter $0$

Answer 1

In $△ABC$
$\tan 60=\frac{AB}{BC}$
$AB=\sqrt{3}BC$
Let $BC=x$, $AB=\sqrt{3}x$
In $△ABD$,
$\tan 30=\frac{AB}{BD}$
$BD=AB\sqrt{3}$
$BC+CD=AB\sqrt{3}$
$x+20=x\sqrt{3}\left(\sqrt{3}\right)$
$x+20=3x$
$x=10$
Thus, BC = 10, AB = 17.32 cm