AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm and divides the circle into two segments. Find the area of the minor segment.

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Solution

As radius of the circle = 4 cm
Length of the chord is also = 4cm
The triangle so obtained here is an equilateral triangle.
In equilateral triangle each angle measures 60°
So, Central angle θ = 60°Area of the sector
= πr^2θ/360

Area of sector= 60/360x 3.14x4x4

=8.37cm sq.

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AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm and divides the circle into two segments. Find the area of the minor segment.

As radius of the circle = 4 cm Length of the chord is also = 4cm The triangle so obtained here is an equilateral triangle. In equilateral triangle each angle measures 60° So, Central angle θ = 60°Area of the sector = πr^2θ/360 Area of sector= 60/360x 3.14x4x4 =8.37cm sq.

As radius of the circle = 4 cm
Length of the chord is also = 4cm
The triangle so obtained here is an equilateral triangle.
In equilateral triangle each angle measures 60°
So, Central angle θ = 60°Area of the sector
= πr^2θ/360

Area of sector= 60/360x 3.14x4x4

=8.37cm sq.