AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm. Find the area of the sector of the circle formed by chord AB.

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Solution

Here, radius of the circle = 4 cm

Length of the chord = 4 cm

So, the triangle formed by the cord and two radius is an equilateral triangle of side 4 cm.

We know that in an equilateral triangle each angle measures $60^{o}$

So, area of sector $= π r^{2} \times \frac{θ}{360^{o}}$

$= \frac{22}{7} \times 4^{2} \times \frac{60}{360}$

$= 8.38 c m^{2}$

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AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm. Find the area of the sector of the circle formed by chord AB.

Here, radius of the circle = 4 cm Length of the chord = 4 cm So, the triangle formed by the cord and two radius is an equilateral triangle of side 4 cm. We know that in an equilateral triangle each angle measures 60o So, area of sector =πr2×θ360o =227×42×60360 =8.38 cm2