AB is a chord of a circle with centre O.

$∠ x = 90^{\circ}$

True

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False

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Solution

The correct option is A
True

The line drawn through the centre of a circle perpendicularly bisects a chord.
Hence, $∠ x = 90^{\circ}$ .

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Similar questions

AB is a chord of a circle with centre O.

$∠ x = 90^{\circ}$

If AB is a chord of a circle with centre O. Then $∠ x = 90^{\circ}$ .

AB is a chord of a circle with centre O.
AC = CB,
$∠ x = 90^{\circ}$

AB is a chord of a circle with centre O.
The chord is bisected at the foot of the perpendicular.

Hence, $∠ x = 90^{\circ}$

If AB is a chord of a circle with center O, then $x = 90^{\circ}$

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