AB is a chord of a circle with centre O.
∠x=90∘
90°
80°
The line drawn through the centre of a circle perpendicularly bisects a chord. Hence, ∠x=90∘.
If AB is a chord of a circle with centre O. Then ∠x=90∘.
AB is a chord of a circle with centre O. AC = CB, ∠x=90∘
AB is a chord of a circle with centre O. The chord is bisected at the foot of the perpendicular.
Hence, ∠x=90∘
If AB is a chord of a circle with center O, then x=90∘