AB is a chord of a circle with centre O.
The chord is bisected at the foot of the perpendicular.

Hence, $∠ x = 90^{\circ}$

90°

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80°

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Solution

The correct option is A
90°

The line drawn through the centre of a circle to bisect a chord is perpendicular to the chord.
Hence, $∠ x = 90^{\circ}$ .

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