Question

$AB$ is a diameter of a circle. $CD$ is a chord parallel to $AB$ and $2CD=AB$. The tangent at $B$ meets the line $AC$ produced at $E$ then $AE$ is equal to-

• A. $AB$
• B. $\sqrt{2}AB$
• C. $2\sqrt{2}AB$
• D. $2AB$

Answer 1

Answer: (D)

$2AB$

$\angle CAB={60}^o$
In $△ABE$
$\cos {60}^o=\frac{AB}{AE}$
$\Rightarrow$ $AE=2AB$