AB is a diameter of the circle APBR as shown in the figure. APQ and RBQ are straight lines. Select the statements that are true.
∴ ∠ PRB=35∘
∴ ∠ BPQ=90∘
∠ BPR=30∘
∠ PBR=115o
∠ PRB=∠ BAP (Angles in the same segment)
∴ ∠ PRB=35∘
In Δ ABP, ∠ APB=90∘ (Angle in semi circle)
∴ ∠ BPQ=90∘
In Δ PQR
∠ R+∠ Q+∠ RPQ=180∘
⇒ 35∘+25∘+∠ RPQ=180∘
∴ ∠ RPQ=180∘−60∘=120∘
∴ ∠ BPR=∠ RPQ−∠ BPQ
=120∘−90∘=30∘
In Δ PBR,
∠ PBR=180∘−(∠ R+∠ BPR)
=180∘−(35∘+30∘)=180∘−65∘
=115∘