Question

$AB$ is a line segment.$P$ and $Q$ are points on oposite sides of $AB$ such that each of them is equidistant from the points $A$ and $B$.Show that $△PAQ\cong △PBQ$

Answer 1

In $△PAQ$ and $△PBQ$

$PA=PB$(given)

$QA=QB$(given)

$PQ=PQ$(common)

So,$△PAQ\cong △PBQ$ by SSS rule.