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Question

'AB' is a two-digit number whose digits are A and B. If 'AB' is divisible by 5 but not divisible by 2 and BA is divisible 3. Then which of the following are possible values of A and B?


A

(x-2)(x-5)= – 7x + 10

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B

(x+2) (x-2) = - 4

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C
A=7,B=5
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D
A=4,B=0
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Solution

The correct options are
B

(x+2) (x-2) = - 4


C A=7,B=5

AB is divisible by 5. Thus B should be either 0 or 5. But since AB is not divisible by 2, B is surely 5.
Since BA is divisible by 3, A+B should also be divisible by 3.
But B is 5. Thus A + 5 should also be divisible by 3.
Among the options, A+5 will be divisible by 3 A=4 or A=7.


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