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Question

AB is parallel to CD, EF intersects them at M and N. The bisectors of BMN and MND meet at Q. If AME=80, then find MQN.

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Solution

Given: AME=80
So, BMF=AME=80
( Vertically opposite angles)
QMN=12BMF=12×80=40
( QM bisects BMF)
Also, CNE=AME=80
( Corresponding angles)
So, CNE+END=180
( CD is a straight line)
80+END=180
END=100
QNM=12END=12×100=50
( QN bisects END)
In ΔQMN,
MQN+QMN+QNM=180
MQN+40+50=180
MQN=90

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