AB is tangent to the circle with centre O at A and $O A = A B$
Find $∠ O A B$ .

30^{\circ}

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45^{\circ}

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60^{\circ}

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90^{\circ}

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Solution

The correct option is D $90^{\circ}$
Line joining centre to the point of contact of tangent makes $90^{\circ}$ with tangent.
So, option D is correct.

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