Question

AB
×BA
------------
(B+1) C B
-------------

Answer 1

We have : AB × BA = ( B + 1 )CB

Here we have two digit number multiplied by same two digit with different place value , that gives three digit number .

So, we check

20 ×02 = 40 ( That only gives us 2 digit number )

19 × 91 = 1729 ( That gives four digit number )

18 × 81 = 1458 ( That gives four digit number )

17 × 71 = 1207 ( That gives four digit number )

16 × 61 = 976 ( That gives three digit number ) , But we can't write 9 = B + 1 where B = 6

15 × 51 = 765 ( That gives three digit number ) , But we can't write 7 = B + 1 where B = 5

14 × 41 = 574 ( That gives three digit number ) , Here we can write 5 = B + 1 where B =4

SO, we can say

A = 1 , B = 4 and C = 7 ( Ans )

And
13 × 31 = 403 ( That gives three digit number ) , Here we can write 4 = B + 1 where B = 3

SO, we can say

A = 1 , B = 3 and C = 0 ( Ans )