ABC+ABC+ABC=BBB
Find A,B ,C
With proper method.
A B C
+A B C
+A B C
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B B B
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so, we may have 3*C = B or 3 C = 10 + B or 3 C = 20 + B
1) if 3 C = B
then middle digits: B+B+B = 3 B = 10+B or 20+B
=> B = 5 or 10. But B should be multiple of 3 as 3 C = B.
so this is not possible.
2) if 3 C = 10 + B
then middle digits: 3 B + 1 = 10 + B or 20 + B
then B is a fraction. so it is not right.
3) if 3 C = 20 + B
middle digits: 3 B + 2 = 10 + B or 20 + B
so B = 4 or 10 so, B = 4.
then C = 20+4 / 3 = 8
then the carry to the hundreds place = 1.
So 3 A + 1 = B => A = 1
so the number is 1 4 8.
hence A=1, B=4, C=8 Ans.