- ABC - DEF - ar- ABC -9 cm 2- ar- DEF -16 cm 2- If BC -2-1 cm- then the measure of EF isa 2-8 cmb 4-2 cmc 2-5 cmd 4-1 cm

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Relation between Areas and Sides of Similar Triangles

Δ ABC ∼Δ DEF ...

Question

∆ABC ∼ ∆DEF, ar(∆ABC) = 9 cm², ar(∆DEF) = 16 cm². If BC = 2.1 cm, then the measure of EF is

(a) 2.8 cm
(b) 4.2 cm
(c) 2.5 cm
(d) 4.1 cm

Open in App

Solution

Given:

To find: measure of EF

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

Hence the correct answer is

Suggest Corrections

Similar questions

If $Δ A B C \sim Δ D E F$ such that area of $Δ A B C$ is $9 c m^{2}$ and the area of $Δ D E F$ is $16 c m^{2}$ and BC = 2.1 cm, then the length of EF is

Q. ∆ABC ∼ ∆DEF. If BC = 3 cm, EF = 4 cm and ar(∆ABC) = 54 cm², then ar(∆DEF) =

(a) 108 cm²
(b) 96 cm²
(c) 48 cm²
(d) 100 cm²

If $Δ A B C \sim Δ D E F$ such that area of $Δ A B C$ is $9 c m^{2}$ and the area of $Δ D E F$ is $16 c m^{2}$ and BC = 2.1 cm. Find the length of EF. [2 MARKS]