Question

ABC is a right - angle triangular plate of uniform thickness. The sides are such that AB > BC as shown in figure.$I_1,I_{2}and{I}_3$ are moments of inertia about AB, BC and AC respectively. Then which of the following relations is correct?

• A. $I_1=I_2=I_3$
• B. $I_2>I_1>I_3$
• C. $I_3<I_2<I_1$
• D. $I_3>I_1>I_2$

Answer 1

The correct option is A $I_1=I_2=I_3$

We know that $I=m{r}^2$

$\therefore I\propto r^2$

So moment of inertia depend only on man and perpendicular distance between it and axis of rotation it does not depend $m$ thickness of plane

$\therefore I_1=I_2=I_3$