ABC is a right angled triangle, AB = 3cm, BC = 5 cm and AC = 4cm, then the inradius of the circle is:

1 cm

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1.25 cm

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1.5 cm

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None of these

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Solution

The correct option is A 1 cm
Inradius of an incircle of right angled triangle
$= \frac{B a s e + A l t i t u d e - H y p o t e n u s e}{2} = \frac{4 + 3 - 5}{2} = 1 c m$

Alternatively :
$I n r a d i u s = \frac{A r e a o f t r i a n g l e}{S i m i p e r i m e t e r o f t r i a n g l e} = \frac{\frac{(3 \times 4)}{2}}{\frac{(3 + 4 + 5)}{2}} = \frac{6}{6} = 1 c m$

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Similar questions

Construct a triangle ABC with the following data: AB = 3 cm,BC = 4 cm and AC = 5 cm. Find its inradius.

△ A B C

A B = 3 c m, B C = 4 c m

A C = 5 c m

Δ A B C

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A B = 4 c m, B C = 3 c m

A C = 5 c m

In the given right-angled triangle, if AB = 3 cm, BC = 4 cm, then the length of AC is

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