Question

$ABC$ is a right-angled triangle. Angle $ABC={90}^o,$ $AC=25cm$ and $AB=24cm$. Calculate the area of a $\Delta ABC.$

Answer 1

Using Pythagoras theorem,
${\left(G\right)}^2={\left(B\right)}^2+{\left(P\right)}^2$
${\left(25\right)}^2={\left(B\right)}^2+{\left(24\right)}^2$
$625=\left(B^2\right)+576$
$625-576=B^2$
$49=B^2$
$B=7$
$\therefore$ Area of triangle $=\frac{1}{2}\times B\times h$
$=\frac{1}{2}\times 7\times 24$
$=84c{m}^2$