ABC is a right angled triangle in which ∠A = 90° and AB = AC, Show that ∠B = ∠C.

Open in App

Solution

Given in ΔABC, AB = AC

Join the midpoint D of BC to A.

Now in ΔADC and ΔADB

AD = AD (common)

AC = AB (giyen)

DC = DB (construction)

$\Rightarrow$ ΔADC $≅$ ΔADB

$\Rightarrow$ ∠C = ∠B (CPCT)

Suggest Corrections

Similar questions

∠ A = 90^{\circ}

∠ B = ∠ C

A B C

∠ A = 90^{\circ}

A B = A C

∠ B

∠ C

ABC is a right-angled triangle in which $∠ A = 90^{\circ} a n d A B = A C . F i n d ∠ B a n d ∠ C .$

A = 90^{\circ}

Join BYJU'S Learning Program