Question

ABC is a right-angled triangle in which $\angle A={90}^{\circ }andAB=AC.Find\angle Band\angle C.$

Answer 1

In $\Delta ABC,\angle ={90}^{\circ }$

AB = AC

$\therefore \angle C=\angle B\text{(Angles opposite to equal sides)}$

But $\angle B+\angle C={90}^{\circ }(\because \angle B={90}^{\circ })$

$\therefore \angle B=\angle C=\frac{{90}^{\circ }}{2}={45}^{\circ }$

Hence $\angle B=\angle C={45}^{\circ }$