ABC is a right angled triangle,right angled at B such that BC = 6 cm and AB = 8 cm. A circle with center O is inscribed in $△$ ABC. Find the radius of the circle.

Q. ABC is a right angled triangle, right angled at B such that BC = 6 cm and AB = 8 cm. A circle with centre O is inscribed in Δ ABC. The radius of the circle is

(a) 1 cm

(b) 2 cm

(c) 3 cm

(d) 4 cm

Q. In a right triangle ABC, right angled at B,

B C = 15 c m

, and

A B = 8 c m

. A circle is inscribed in triangle ABC. The radius of the circle is :

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ABC is a right angled triangle right angled at B such that BC=6 cm and AB=8 cm. A circle with center O is inscribed in ΔABC. The radius of the circle is

The correct option is A 2 cmGiven, BC=6 and AB=8using Pythagoras Theorem,AC2=AB2+BC2AC2=62+82AC=10Radius = 2×AreaPerimeterRadius = 2×(12×6×8)10+8+6Radius = 2 cm

ABC is a right angled triangle right angled at B such that $B C = 6$ cm and $A B = 8$ cm. A circle with center O is inscribed in $Δ A B C$ . The radius of the circle is

The correct option is A 2 cm
Given, $B C = 6$ and $A B = 8$
using Pythagoras Theorem,
$A C^{2} = A B^{2} + B C^{2}$
$A C^{2} = 6^{2} + 8^{2}$
$A C = 10$
Radius = $\frac{2 \times A r e a}{P e r i m e t e r}$
Radius = $\frac{2 \times (\frac{1}{2} \times 6 \times 8)}{10 + 8 + 6}$
Radius = $2$ cm