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Moment of Inertia of a Ring

ABC is a righ...

Question

ABC is a right angled triangular plate of uniform thickness. The sides are such that AB > BC as shown in figure. $I_{1}, I_{2}, I_{3}$ are moments of inertia about AB, BC and AC respectively. Then, which of the following relations is correct?

A

I_{1} = I_{2} = I_{3}

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B

I_{2} > I_{1} > I_{3}

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C

I_{3} < I_{2} < I_{1}

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D

I_{3} > I_{1} > I_{2}

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Solution

The correct option is B $I_{2} > I_{1} > I_{3}$
$m o m e n t o f i n e r t i a a b o u t a s i d e i s \frac{M h^{2}}{6} (h i s a l t i t u d e c o r r e s p o n d i n g t o s i d e) c o m p a r i s i o n o n 3 a l t i t u d e s : A B > B C > B D s o o r d e r o f m o m e n t o f i n e r t i a a b o u t a x e s i s B C > A B > A C$

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Similar questions

Q. ABC is right angled triangular plane of uniform thickness. The sides are such that

A B > B C

as shown in figure.

I_{1}, I_{2}, I_{3}

are moments of inertia about AB, BC and AC, respectively. Then which of the following relations is correct?

A B C

is a right angled triangular plate of uniform thickness. The sides are such that

A B > B C

as shown in the figure above.

I_{1}, I_{2}, I_{3}

are moments of inertia about

A B, B C

A C

respectively. Then which of the following relations is correct ?

Q. There is a flat uniform triangular plate ABC such that

A B = 4 cm, B C = 3 cm

∠ A B C = 90^{\circ}

as shown in the figure. The moment of inertia of the plate about AB, BC and CA is

I_{1}, I_{2}

I_{3}

respectively. The incorrect statement is

A B C D

is a square plate with centre

O

. The moment of inertia of the plate about the axes

1, 2, 3

4

I_{1}, I_{2}, I_{3} & I_{4}

respectively. It follows that

Now what should be the correct relation between $I_{1}$ , $I_{2}$ and $I_{3}$ .

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