Question

$ABC$ is a right angles triangle in which $AC=17cm,AB=8cm$ and $BC=15cm$, Write the value of $\tan C,\sec A,\csc C$ and $\cot A$ ?

Answer 1

$AC=17cmAB=8cmBC=15cm⟹\angle B={90}^{\circ }\tan C=\frac{AB}{BC}=\frac{8}{15}\sec A=\frac{AC}{AB}=\frac{17}{8}\csc A=\frac{AC}{BC}=\frac{17}{15}\cot A=\frac{AB}{BC}=\frac{8}{15}$