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Question

ABC is a right triangle, right angled at C. If A = 30 and AB = 40 units, find the remaining two sides and B in ΔABC.

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Solution

We have ,
A+B+C=180
30+B+90=180 [A=30andC=90]

B=180120=60
Now , cosA=ACAB
cos30=AC40

32=AC40
AC=32×40AC=203 units
and , sinA=BCAB

sin30=BC40
12=BC40=40×12=20 units

Hence AC = 203 units , BC=20 units and B=60

1056836_1009084_ans_4a97295aabe94e2691b9d494239c9d1b.png

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