Question

ABC is a right triangle with $\angle B=90°$.
If AB = 1, BC = 1 and AC = $\sqrt{2}$ then $\sin C$ =.

• A. $\frac{1}{\sqrt{2}}$
• B. 2
• C. 1

Answer 1

The correct option is A $\frac{1}{\sqrt{2}}$

In triangle ABC
So,
$\sin C=\frac{Perpendicular}{Hypotenuse}$
$\sin C=\frac{1}{\sqrt{2}}$