Question

abc is a three digit number. This three digit number is reversed and subtracted from the original number. The difference obtained is 396. Find (a-c).

• A. 1
• B. 4
• C. 9
• D. 11

Answer 1

The correct option is B 4

Here, abc is a 3-digit number.

General form of abc = 100a + 10b + c ... (i)

Number obtained by reversing the digits is cba.

General form of cab = 100c + 10b + a ... (ii)

Subtracting (ii) from (i)
$(100a+10b+c)-(100c+10b+a)$
$=(100-1)a+(10-10)b+(1-100)c$
$=99a-99c$
$=99(a-c)$

$\text{Given:}99(a-c)=396$
$\Rightarrow a-c=\frac{396}{99}=4$