ABC is a triangle and P is any point on −−→BC. If −−→PQ is the resultant of the vectors −−→AP,−−→PB and −−→PC then ACQB is :
A
rectangle
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B
square
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C
rhombus
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D
parallelogram
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Solution
The correct option is D parallelogram As, we have −−→PQ=−−→AP+−−→PB+−−→PC −−→PQ−−−→PB=−−→AP+−−→PC −−→PQ−−−→PB=−−−→PA+−−→PC −−→BQ=−−→AC⋯(i)
Similarly, −−→PQ−−−→PC=−−→AP+−−→PB −−→CQ=−−→AB⋯(ii)
So, ACQB is parallelogram