ABC is a triangle . D is a point on AB such that AD=1/4 AB and E is a point on AC such that AE=1/4 AC. Then DE = (in terms of BC )

Open in App

Solution

Suggest Corrections

Similar questions

ABC is a triangle, D is a point on AB such that $A D = \frac{1}{4} A B$ and E is a point on AC such that $A E = \frac{1}{4}$ AC. Prove that DE = $\frac{1}{4} B C$

State true or false:

In triangle

A B C

D

is a point in side

A B

such that

A B = 4 A D

and

E

is a point in

A C

such that

A C = 4 A E

. Hence,

B C : D E = 4 : 1

In triangle ABC, D is a point on AB and E is a point on AC such that DE || BC. If $\frac{A D}{A B}$ = $\frac{A E}{x}$ , Then $x$ is

___.

In triangle ABC, D is a point on AB and E is a point on AC such that DE || BC. If $\frac{A D}{A B}$ = $\frac{A E}{x}$ , Then $x$ is

___.

In triangle ABC, D is a point on AB and E is a point on AC such that DE || BC. If $\frac{A D}{A B}$ = $\frac{A E}{x}$ , Then $x$ is equal to ___.

Join BYJU'S Learning Program