Question

$ABC$ is a triangle in which $AB=AC=4$ cm and $\angle A={90}^{\circ }$. Calculate the area of $△ABC$ (in $c{m}^2$).

Answer 1

Triangle ABC is a right angled triangle. Let AB be the base and AC be the height.
Area of a right angled triangle $=\frac{1}{2}\times base\times height=\frac{1}{2}\times 4\times 4=8{cm}^2$